JSimma
REGISTERED
New to the Forums and curious to know how folks are calculating fixtures in a R-2 dormitory with the UPC fixture table 422.1. As shown in the image link the language notes both "1 per 10 males" as well as "add 1 fixture for each additional 25 males ... " Whereas other fixture designations use "1:1-15, 2: 16-35 ... and then list "over xxx add 1 fixture for xxx additional persons"
2018 UPC image link
So for a dorm with 56 males and 56 females .... how would you apply the calculation?
56 males @ 1 per 10 = 5.6 = 6 toilets or 1 toilet + [ ((56-10) /25) =1.84 ] = 2.84 or 3 toilets?
Other fun math ideas or UPC commentary for solutions?
The State of Nebraska has deleted chapter 29 of the 2018 IBC per it's amendments and references the 2018 UPC
Thanks all!
2018 UPC image link
So for a dorm with 56 males and 56 females .... how would you apply the calculation?
56 males @ 1 per 10 = 5.6 = 6 toilets or 1 toilet + [ ((56-10) /25) =1.84 ] = 2.84 or 3 toilets?
Other fun math ideas or UPC commentary for solutions?
The State of Nebraska has deleted chapter 29 of the 2018 IBC per it's amendments and references the 2018 UPC
Thanks all!