And as if this subject wasn't titillating enough ... I just received this explanation from ICC staff engineers:
Q: Table 1609.6.2(2) refers to Conditions 1 and 2 for Windward roof slopes, how do I find out what Conditions 1 and 2 mean?
A: This is not a simple question to answer. First of all the conditions 1 and 2 has nothing to do with how the building is constructed or how strong the wind is blowing.
To understand how the two wind load conditions are derived in Table 1609.6.2(2), one must understand how and where the values in the table come from. The basis is Cnet = Kd [(G) (Cp) – (GCpi)] (see Section 1609.6.2) and the values obtained for Cp.
When considering the possible wind loads for the “windward roof slope,” please refer to the illustrations of Figure 6-6 of ASCE 7-05, where you will notice that on windward side of the sloping roof of the “Gable, Hip Roof”, there are two wind load conditions, one “upward” and the other “downward” as illustrated by the two arrows. Both conditions on the windward roof slope will provide two values of Cp and thereby providing two values of Cnet per Table 1609.6.2(2), see example below:
For an enclosed building with a simple gable roof (slope < 2:12 or 10 degrees), Table 1609.6.2(2) shows, reading across Windward roof slopes: Slope < 2:12 (10 degrees), we have:
Condition 1, Cnet = -1.09 for + Internal Pressure of Enclosed Building
Condition 1, Cnet = -0.79 for – Internal Pressure of Enclosed Building
Condition 2, Cnet = -0.28 for + Internal Pressure of Enclosed Building
Condition 2, Cnet = +0.02 for – Internal Pressure of Enclosed Building
How are these value obtained in the table? These values are obtained by solving:
Cnet = Kd [(G) (Cp) – (GCpi)], where:
Kd = 0.85 per ASCE 7, Table 6-4
GCpi = plus or minus 0.18 for enclosed building per ASCE 7, Figure 6-5
G = 0.85 per ASCE 7, Section 6.5.8.1
Cp = -1.30 (wind load condition 1) and -0.18 (wind load condition 2) per ASCE 7, Figure 6-6 (bottom table for “Roof Pressure Coefficients, Cp” going down the column for 10 (degrees) for h/L > 1.0.
By plugging in these values, we get:
Condition 1, Cnet = 0.85 [(0.85) (-1.30) – (+0.18)] = -1.09 for + Internal Pressure of Enclosed Building
Condition 1, Cnet = 0.85 [(0.85) (-1.30) – (– 0.18)] = -0.79 for – Internal Pressure of Enclosed Building
Condition 2, Cnet = 0.85 [(0.85) (-0.18) – (+0.18)] = -0.28 for + Internal Pressure of Enclosed Building
Condition 2, Cnet = 0.85 [(0.85) (-0.18) – (– 0.18)] = +0.02 for – Internal Pressure of Enclosed Building