Mech
REGISTERED
2009 IBC
1. Section 506.2.1: If a building has a uniform W value of 40 around the entire building, can I use a value of 40 in equation 5-1 (If = [F / P - 0.25]W / 30), or must it be reduced to 30? I haven’t found a maximum allowable value for a uniform W value.
2. Suppose a type 2B, single story 200 ft x 200 ft structure has an open space of 30 ft, and it also has a fire wall separating the structure into two separate buildings. The fire wall is 150 ft from one end of the structure and the first building is group B with 30,000 sf and the second building is S-1 with 10,000 sf.
Am I correct in my reasoning: for the group B building, the perimeter (P) is 200 (outside wall) + 150 (outside wall) + 150 (outside wall) + 200 (shared fire wall) = 700 ft. The building perimeter that fronts on an open space (F) is 500 ft, because the 200 ft shared fire wall has a building next to it and is therefore not open. From eq. 5-1, If = [ 500 / 700 – 0.25] (30) / 30 = 0.464 (an allowable area increase of 46.4%.)
And then the S-1 perimeter (P) is 200 + 50 + 50 +200 (fire wall) = 500 sf and the perimeter fronting an open space (F) is 200 + 50 + 50 = 300 sf? If = [300 / 500 – 0.25] (30) / 30 = 0.35 (an allowable area increase of 35%.)
Someone in my office is saying that the perimeter (P) and perimeter fronting the open space (F) is 200 + 200 + 200 + 200 = 800 ft, so the value of F/P is 800 / 800 = 1 for the structure. If = [800 / 800 – 0.25] (30) / 30 = 0.75. They want to increase the allowable area for group B building 75% and the group S building 75%. Is this correct? I think it is not.
Thanks in advance.
1. Section 506.2.1: If a building has a uniform W value of 40 around the entire building, can I use a value of 40 in equation 5-1 (If = [F / P - 0.25]W / 30), or must it be reduced to 30? I haven’t found a maximum allowable value for a uniform W value.
2. Suppose a type 2B, single story 200 ft x 200 ft structure has an open space of 30 ft, and it also has a fire wall separating the structure into two separate buildings. The fire wall is 150 ft from one end of the structure and the first building is group B with 30,000 sf and the second building is S-1 with 10,000 sf.
Am I correct in my reasoning: for the group B building, the perimeter (P) is 200 (outside wall) + 150 (outside wall) + 150 (outside wall) + 200 (shared fire wall) = 700 ft. The building perimeter that fronts on an open space (F) is 500 ft, because the 200 ft shared fire wall has a building next to it and is therefore not open. From eq. 5-1, If = [ 500 / 700 – 0.25] (30) / 30 = 0.464 (an allowable area increase of 46.4%.)
And then the S-1 perimeter (P) is 200 + 50 + 50 +200 (fire wall) = 500 sf and the perimeter fronting an open space (F) is 200 + 50 + 50 = 300 sf? If = [300 / 500 – 0.25] (30) / 30 = 0.35 (an allowable area increase of 35%.)
Someone in my office is saying that the perimeter (P) and perimeter fronting the open space (F) is 200 + 200 + 200 + 200 = 800 ft, so the value of F/P is 800 / 800 = 1 for the structure. If = [800 / 800 – 0.25] (30) / 30 = 0.75. They want to increase the allowable area for group B building 75% and the group S building 75%. Is this correct? I think it is not.
Thanks in advance.