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Testing Concrete Volume Calculator - Need Help Testing

jar546 said:
give me some feedback
Click to expand...
Nice, this works well.

You might consider putting the “OR enter Area (if known)” field above the Thickness field because the “or” applies to Length and Width, not Thickness.

Just an observation, looks like a non-zero value in the Area field overrides Length and Width if they have any values, so the instructional text “If you enter area, leave length and width blank” really doesn’t apply. Maybe revise the note to say, “Value for Area overrides values entered in Length or Width”?

Once you get your calculators all set up you could add a link on each calculator page to the page on the forum where you have all your calculators listed.
 
walker.t said:
Nice, this works well.

You might consider putting the “OR enter Area (if known)” field above the Thickness field because the “or” applies to Length and Width, not Thickness.

Just an observation, looks like a non-zero value in the Area field overrides Length and Width if they have any values, so the instructional text “If you enter area, leave length and width blank” really doesn’t apply. Maybe revise the note to say, “Value for Area overrides values entered in Length or Width”?

Once you get your calculators all set up you could add a link on each calculator page to the page on the forum where you have all your calculators listed.
Click to expand...
Great feedback. Thank you.
 
SCBO1 said:
Pier cylinders? for our deck building friends? Not sure there's a calculator for a cone shaped pier?
Click to expand...
Do you mean the frustum of a cone? I.e. a cone with a shorter cone cut off the top? You can calculate the volume based on that description and the formula for the volume of a cone, which for height H and bottom radius r is 1/3 * pi * r^2 * H:

Say the frustum has height h and top radius r1 and bottom radius r2, if you extend that into a cone, the cone height H would be such that r2/H = r1/(H-h). Solving for H gives H = h * r2 / (r2-r1). So the frustrum volume is pi/3 * h * (r2^2*r2/(r2-r1) - r1^2*(r1/(r2-r1)) = pi/3 * (r1^2 + r1*r2 + r2^2) * h.

Cheers, Wayne
 
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wwhitney said:
Do you mean the frustum of a cone? I.e. a cone with a shorter cone cut off the top? You can calculate the volume based on that description and the formula for the volume of a cone, which for height H and bottom radius r is 1/3 * pi * r^2 * H:

Say the frustum has height h and top radius r1 and bottom radius r2, if you extend that into a cone, the cone height H would be such that r2/H = r1/(H-h). Solving for H gives H = h * r2 / (r2-r1). So the frustrum volume is pi/3 * h * (r2^2*r2/(r2-r1) - r1^2*(r1/(r2-r1)) = pi/3 * (r1^2 + r1*r2 + r2^2) * h.

Cheers, Wayne
Click to expand...
Ok so let's test out Wayne's formula:

 
I could just calculate the radius x the height and ÷ by 2 and be pretty close to reduce my aspirin intake after following Wayne's calcs!:eek:
 
I was always confused by the two electric trains, one from NY and one from LA and they collide in Chicago and which way the smoke goes?
 
SCBO1 said:
I could just calculate the radius x the height and ÷ by 2 and be pretty close to reduce my aspirin intake after following Wayne's calcs!:eek:
Click to expand...
Which radius? The correct formula is not that complicated once you derive it. Note that for r1 = r2, the frustrum formula reduces to the expected formula for the volume of a cylinder. Edit: likewise for r1 = 0, the formula reduces to the expected formula for the volume of a cone.

Cheers, Wayne
 
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